-2y^2+2y+(y-5)^2-(32)=0

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Solution for -2y^2+2y+(y-5)^2-(32)=0 equation: 



-2y^2+2y+(y-5)^2-(32)=0

We move all terms containing y to the left, all other terms to the right

-2y^2+2y+(y-5)^2=32

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